Chemical Thermodynamics Question 412

Question: A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of $ 37.0{}^\circ C $ . As it does so, it absorbs 208 J of heat. The values of q and w for the process will be: $ ( R=8.314J/molK )( \text{ln }7.5=2.01 ) $

Options:

A) $ q=+208,J,w=-208J $

B) $ q=-208,J,w=-208J $

C) $ q=-208,J,w=+208J $

D) $ q=+208J,w=+208J $

Show Answer

Answer:

Correct Answer: A

Solution:

  • Process is isothermal reversible expansion, hence $ \Delta U=0 $ , therefore $ q=-w $ . Since $ q=+208J,W=-208J $


NCERT Chapter Video Solution

Dual Pane