Chemical Thermodynamics Question 384

Options:

A) $ K_{P}=-RT $ In $ \Delta {{G}^{{}^\circ }} $

B) $ K_{P}={{[ \frac{e}{RT} ]}^{\Delta {{G}^{{}^\circ }}}} $

C) $ K_{P}=-\frac{\Delta G}{RT} $

D) $ K_{P}={{e}^{-\Delta {{G}^{{}^\circ }}/RT}} $

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Answer:

Correct Answer: D

Solution:

  • $ \Delta G=-RT $ ln $ K_{P} $ or $ K_{P}={{e}^{-\Delta G/RT}} $


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