Chemical Thermodynamics Question 380

Question: One mole of an ideal gas is expanded isothermally and reversibly to half of its initial pressure. $ \Delta S $ for the process in $ J{{K}^{-1}}mo{{l}^{-1}} $ is $ [ln2=0.693,and,R=8.314,J/(mol,K)] $

Options:

A) 6.76

B) 5.76

C) 10.76

D) 8.03

Show Answer

Answer:

Correct Answer: B

Solution:

  • For isothermal process $ ( \Delta T=0 ) $

$ \Delta S=R\ell n\frac{P_1}{P_2}=8.314\ell n,2, $

$ =8.314\times 0.693=5.76 $



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