Chemical Thermodynamics Question 377

Question: What is the free energy change for the conversion of 1 mole of water into steam at $ 373.2K $ . The heat of vaporization $ ( \Delta ,H_{v} ) $ of water of $ 373.2K $ is $ 9.1kcalmo{{l}^{-1}} $ . The entropy change is 25.5 cal/mol deg.

Options:

A) $ -401.6cal/mol $

B) $ -416.6cal/mol $

C) $ 516.5cal/mol $

D) $ -516.5cal/mol $

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Answer:

Correct Answer: B

Solution:

  • $ \Delta G=\Delta H-T\Delta S $

$ \therefore \Delta G=9100-373.2\times 25.5=-416.6calmo{{l}^{-1}} $



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