Chemical Thermodynamics Question 364

Question: $ 36mL $ of pure water takes 100 sec to evaporate from a vessel and heater connected to an electric source which delivers 806 watt. The $ \Delta H_{vap} $ of $ H_2O $ is:

Options:

A) $ 40.3kJ/mol $

B) $ 43.2kJ/mol $

C) $ 4.03kJ/mol $

D) None of these

Show Answer

Answer:

Correct Answer: A

Solution:

  • 1 watt = 1 J/sec Total heat supplied for $ 36mL,H_2O $

$ =806\times 100 $

$ =80600J $

$ \Delta H_{vap}=\frac{80600}{36}\times 18 $

$ =40300Jor40.3kJ/mol $



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