Chemical Thermodynamics Question 317

Question: The value of enthalpy change ( ΔH ) for the reaction C2H2OH(l)+3O2(g)2CO2(g)+3H2O(l) a 27C is -1366.5 kJ mol1 . The value of internal energy change for the above reaction at this temperature will be

Options:

A) -1371.5 kJ

B) -1369.0 kJ

C) -1364.0 kJ

D) -1361.5 kJ

Show Answer

Answer:

Correct Answer: C

Solution:

  • Relation between ΔH (enthalpy change) and ΔE (internal energy change) is ΔH=ΔE+ΔngRT Where Δng =(moles of gaseous products)-(moles of gaseous reactants) For the given reaction, Δng=23=1

1366.5=ΔE1×8.314×103×300

ΔE=1364.0kJ,mol1



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