Chemical Thermodynamics Question 316

Question: Evaluate ΔU at 500 K for the process Mg(s)+2HCl(g)MgCl2(s)+H2(g)ΔH=109 kcal The volume change of solids to be ignored

Options:

A) -204 kcal

B) -108 kcal

C) -9 kcal

D) +9 kcal

Show Answer

Answer:

Correct Answer: B

Solution:

  • ΔH=ΔU+ΔngRT

109=ΔU+(1×2×5001000)kcal

109=ΔU1,kcal

ΔU=109+1=108,kcal



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