Chemical Thermodynamics Question 309

Question: The enthalpy of combustion of methane at $ 25^{o}C $ is $ 890,kJ $ . The heat liberated when $ 3.2,g $ of methane is burnt in air is [KCET 2004]

Options:

A) $ 445,kJ $

B) $ 278,kJ $

C) $ -890,kJ $

D) $ 178,kJ $

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Answer:

Correct Answer: D

Solution:

1 mole (i.e.,) $ 16gm $ of methane on combustion liberate $ 890,kJ $

$ \therefore $ $ 3.2,gm $ will liberate $ =\frac{890\times 3.2}{16} $

$ =178,KJ $



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