Chemical Thermodynamics Question 271

Question: $ H_2(g)+Cl_2(g)\to 2HCl(g),.,\Delta H=-44kcal $

$ 2Na(s)+2HCl(g)\to 2NaCl(s)+H_2(g), $

$ \Delta H=-152,kcal $ For the reaction $ Na(s)+\frac{1}{2}Cl_2(g)\to NaCl(s),,\Delta H= $ [KCET 2000]

Options:

A) - 108 kcal

B) - 196 kcal

C) - 98 kcal

D) 54 kcal

Show Answer

Answer:

Correct Answer: B

Solution:

By (i) + (ii) ; $ Na+\frac{1}{2}Cl_2\to NaCl,,\Delta H=-196,kcal $ .



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