Chemical Thermodynamics Question 251
Question: For the reaction $ A(g)+2B(g)\to 2C(g)+3D(g) $ , the value of $ \Delta E $ at $ 27^{o}C $ is 19.0 kcal. The value of $ \Delta H $ for the reaction would be $ (R=2.0,cal,{{K}^{-1}}mo{{l}^{-1}}) $ [Roorkee Qualifying 1998]
Options:
A) 20.8 kcal
B) 19.8 kcal
C) 18.8 kcal
D) 20.2 kcal
Show Answer
Answer:
Correct Answer: D
Solution:
Use $ \Delta H=\Delta E+\Delta n,RT $
$ \Delta H=19+2\times 2\times {{10}^{-3}}\times 300 $
$ =20.2,kcal $ ; $ \Delta n=2 $ .
