Chemical Thermodynamics Question 219

Question: The difference between heats of reaction at constant pressure and at constant volume for the reaction $ 2C_6H_6(l)+15O_2(g)\to 12CO_2(g)+6H_2O(l) $ at $ 25^{o}C $ in kJ is [IIT JEE 1991; Kerala PMT 2004]

Options:

A) -7.43

B) + 3.72

C) -3.72

D) + 7.43

Show Answer

Answer:

Correct Answer: A

Solution:

$ \Delta H-\Delta E=\Delta nRT $

$ =3\times 8.314\times 298 $

$ =-7432J=-7.43,kJ. $



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