SATHEE: Chemical Thermodynamics Question 168

Chemical Thermodynamics Question 168

Question: Thermochemical reactions $C (g r a p h i t e) + \frac{1}{2} O_{2} (g) \to C O (g);, Δ H = - 110.5, k J$

$C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g);, Δ H = - 283.2, k J$ From the above reaction, the heat of reaction for $C (g r a p h i t e) + O_{2} (g) \to C O_{2} (g)$ will be [CPMT 1988; MP PMT 1989]

Options:

A) - 393.7 kJ

B) + 393.7 kJ

C) - 172.7 kJ

D) + 172.7 kJ

Show Answer

Answer:

Correct Answer: A

Solution:

eq. (i ) + eq. (ii ) gives the required result.

Chemical Thermodynamics Question 168

Question: Thermochemical reactions $C (g r a p h i t e) + \frac{1}{2} O_{2} (g) \to C O (g);, Δ H = - 110.5, k J$

Options:

Answer:

Solution:

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Chemical Thermodynamics Question 168

Question: Thermochemical reactions C(graphite)+12O2(g)→CO(g);,ΔH=−110.5,kJ

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Thermochemical reactions $C (g r a p h i t e) + \frac{1}{2} O_{2} (g) \to C O (g);, Δ H = - 110.5, k J$