Chemical Thermodynamics Question 138

Options:

A) $ \Delta H=\Delta U $

B) $ \Delta H=\Delta U+3RT $

C) $ \Delta H=\Delta U+RT $

D) $ \Delta H=\Delta U-3RT $

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Answer:

Correct Answer: D

Solution:

$ A(s)+3B(g)\to 4C(s)+D(l) $

$ \Delta ng=0-3=-3 $ ; $ \Delta H=\Delta E+\Delta ngRT $

$ [\because \Delta E=\Delta U] $

$ \therefore \Delta H=\Delta U+(-3),(RT) $

$ \Delta H=\Delta U-3,(RT) $ ; $ \Delta H=\Delta U-3RT $



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