SATHEE: Chemical Thermodynamics Question 138

Chemical Thermodynamics Question 138

Options:

A) $Δ H = Δ U$

B) $Δ H = Δ U + 3 R T$

C) $Δ H = Δ U + R T$

D) $Δ H = Δ U - 3 R T$

Show Answer

Answer:

Correct Answer: D

Solution:

$A (s) + 3 B (g) \to 4 C (s) + D (l)$

$Δ n g = 0 - 3 = - 3$ ; $Δ H = Δ E + Δ n g R T$

$[∵ Δ E = Δ U]$

$∴ Δ H = Δ U + (- 3), (R T)$

$Δ H = Δ U - 3, (R T)$ ; $Δ H = Δ U - 3 R T$

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Chemical Thermodynamics Question 138

Question: For the reaction, A(s)+2B(g)→4C(s)+D(l) . ΔH and ΔU are related as — [Orissa JEE 2004]

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Question: For the reaction, $A_{(s)} + 2 B_{(g)} \to 4 C_{(s)} + D_{(l)}$ . $Δ H$ and $Δ U$ are related as — [Orissa JEE 2004]