Chemical Thermodynamics Question 137
Question: The work done during the expansion of a gas from a volume of $ 4dm^{3} $ to $ 6dm^{3} $ against a constant external pressure of $ 3atm $ is ( $ 1L,atm,=101.32,J $ ) [CBSE PMT 2004]
Options:
A) + 304 J
B) -304 J
C) - 6 J
D) -608 J
Show Answer
Answer:
Correct Answer: D
Solution:
$ W=-p\Delta V $ ; $ W=-3\times (6-4) $
$ W=-6\times 101.32 $ ( $ \therefore ,1,L,atm,=101.32,J $ ) $ W=-608,J $
