Chemical Thermodynamics Question 137

Question: The work done during the expansion of a gas from a volume of $ 4dm^{3} $ to $ 6dm^{3} $ against a constant external pressure of $ 3atm $ is ( $ 1L,atm,=101.32,J $ ) [CBSE PMT 2004]

Options:

A) + 304 J

B) -304 J

C) - 6 J

D) -608 J

Show Answer

Answer:

Correct Answer: D

Solution:

$ W=-p\Delta V $ ; $ W=-3\times (6-4) $

$ W=-6\times 101.32 $ ( $ \therefore ,1,L,atm,=101.32,J $ ) $ W=-608,J $



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