Chemical Kinetics Question 87
Question: The rate constant for the reaction, $ 2N_2O_5\to 4NO_2 $ $ +O_2 $ is $ 3\times {10^{-5}}{{\sec }^{-1}} $ . If the rate is $ 2.40\times {10^{-5}}mollitr{e^{\text{-1}}}{{\sec }^{-1}} $ . Then the concentration of $ N_2O_5 $ (in mol litre-1) is [IIT Screening 2000]
Options:
A) 1.4
B) 1.2
C) 0.04
D) 0.8
Show Answer
Answer:
Correct Answer: D
Solution:
Rate = $ K(N_2O_5) $ hence $ 2.4\times {10^{-5}}=3.0\times {10^{-5}}(N_2O_5) $ or $ (N_2O_5) $
$ =0.8mol{l^{-1}} $
