SATHEE: Chemical Kinetics Question 322

Chemical Kinetics Question 322

Question: Consider the reaction: $N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g)$ The equality relationship between $\frac{d [N H_{3}]}{d t}$ and $- \frac{d [H_{2}]}{d t}$ is

Options:

A) $+ \frac{d [N H_{3}]}{d t} = - \frac{2}{3} \frac{d [H_{2}]}{d t}$

B) $+ \frac{d [N H_{3}]}{d t} = - \frac{3}{2} \frac{d [H_{2}]}{d t}$

C) $\frac{d [N H_{3}]}{d t} = - \frac{d [H_{2}]}{d t}$

D) $\frac{d [N H_{3}]}{d t} = - \frac{1}{3} \frac{d [H_{2}]}{d t}$

Show Answer

Answer:

Correct Answer: A

Solution:

[a] If we write rate of reaction in terms of concentration of $N H_{3}$ and $H_{2}$ then Rate of reaction $= \frac{1}{2} \frac{d [N H_{3}]}{d t} = - \frac{1}{3} \frac{d [H_{2}]}{d t}$ So, $= \frac{d [N H_{3}]}{d t} = - \frac{2}{3} \frac{d [H_{2}]}{d t}$

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Chemical Kinetics Question 322

Question: Consider the reaction: N2(g)+3H2(g)→2NH3(g) The equality relationship between d[NH3]dt and −d[H2]dt is

Options:

Answer:

Solution:

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Question: Consider the reaction: $N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g)$ The equality relationship between $\frac{d [N H_{3}]}{d t}$ and $- \frac{d [H_{2}]}{d t}$ is