SATHEE: Chemical Kinetics Question 321

Chemical Kinetics Question 321

Question: A reaction proceeds by first order, 75% of this reaction was completed in 32 min. The time required for 50% completion is

Options:

A) 8 min

B) 16 min

C) 20 min

D) 24 min

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Given: 75% reaction gets completed in 32 min Thus, $k = \frac{2.303}{t} \log \frac{a}{(a - x)}$

$= \frac{2.303}{32} \log \frac{100}{(100 - 75)}$

$= \frac{2.303}{0.0433} \log 4 = 0.0433, m i n^{- 1}$ Now we can use this value of k to get the value of time required for 50% completion of reaction $t = \frac{2.303}{k} \log \frac{a}{(a - x)} = \frac{2.303}{0.0433} \log \frac{100}{50}$

$= \frac{2.303}{0.0433} \log 2 = 16, min$

Chemical Kinetics Question 321

Question: A reaction proceeds by first order, 75% of this reaction was completed in 32 min. The time required for 50% completion is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Chemical Kinetics Question 321

Question: A reaction proceeds by first order, 75% of this reaction was completed in 32 min. The time required for 50% completion is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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