Chemical Kinetics Question 321

Question: A reaction proceeds by first order, 75% of this reaction was completed in 32 min. The time required for 50% completion is

Options:

A) 8 min

B) 16 min

C) 20 min

D) 24 min

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Given: 75% reaction gets completed in 32 min Thus, $ k=\frac{2.303}{t}\log \frac{a}{(a-x)} $

$ =\frac{2.303}{32}\log \frac{100}{(100-75)} $

$ =\frac{2.303}{0.0433}\log 4=0.0433,mi{n^{-1}} $ Now we can use this value of k to get the value of time required for 50% completion of reaction $ t=\frac{2.303}{k}\log \frac{a}{(a-x)}=\frac{2.303}{0.0433}\log \frac{100}{50} $

$ =\frac{2.303}{0.0433}\log 2=16,\min $



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