SATHEE: Chemical Kinetics Question 316

Chemical Kinetics Question 316

Question: The instantaneous rate of disappearance of $M n O_{4}^{-}$ ion in the following reaction is

$4.56 \times 10^{- 3} M s^{- 1} 2 M n O_{4}^{-} + 10 I^{-} + 16 H^{+} \to$

$2 M n^{2 +} + 5 I_{2} + 8 H_{2} O$ The rate of appearance $I_{2}$ is:

Options:

A) $4.56 \times 10^{- 4} M s^{- 1}$

B) $1.14 \times 10^{- 2} M s^{- 1}$

C) $1.14 \times 10^{- 3} M s^{- 1}$

D) $5.7 \times 10^{- 3} M s^{- 1}$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Given $- \frac{d M n O_{4}^{-}}{d t} = 4.56 \times 10^{- 3} M s^{- 1}$ From the reaction given, $- \frac{1}{2} \frac{d M n O_{4}^{-}}{d t} = \frac{4.56 \times 10^{- 3}}{2} M s^{- 1}$

$- \frac{1}{2} \frac{d M n O_{4}^{-}}{d t} = \frac{1}{5} \frac{d I_{2}}{d t}$
$∴ - \frac{5}{2} \frac{d M n O_{4}^{-}}{d t} = \frac{d I_{2}}{d t}$ On substituting the given value
$∴ \frac{d I_{2}}{d t} = \frac{4.56 \times 10^{- 3} \times 5}{2} = 1.14 \times 10^{- 2} M / s$

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Chemical Kinetics Question 316

Question: The instantaneous rate of disappearance of MnO4− ion in the following reaction is

Options:

Answer:

Solution:

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Question: The instantaneous rate of disappearance of $M n O_{4}^{-}$ ion in the following reaction is