Chemical Kinetics Question 273

Question: For a reaction, the rate constant is expressed as k=Ae40000/T . The energy of the activation is

Options:

A) 40000 cal

B) 88000 cal

C) 80000 cal

D) 8000 cal

Show Answer

Answer:

Correct Answer: C

Solution:

[c] k=AeEa/RT
EaR=40000
Ea=40000×2=80000,cal



NCERT Chapter Video Solution

Dual Pane