Chemical Kinetics Question 247
Question: Velocity constant of a reaction at 290 K was found to be $ 3.2\times {10^{-3}} $ . At 310 K it will be about [KCET 1989, 91]
Options:
A) $ 1.28\times {10^{-2}} $
B) $ 9.6\times {10^{-3}} $
C) $ 6.4\times {10^{-3}} $
D) $ 3.2\times {10^{-4}} $
Show Answer
Answer:
Correct Answer: A
Solution:
For 10K rise in temperature, the rate of reaction nearly doubles.
