SATHEE: Chemical Kinetics Question 240

Chemical Kinetics Question 240

Question: For the reaction $N_{2} + 3 H_{2} \to 2 N H_{3}$ if $\frac{Δ [N H_{3}]}{Δ t} = 2 \times 10^{- 4} m o l, l^{- 1} s^{- 1},$ the value of $\frac{- Δ [H_{2}]}{Δ t}$ would be [MP PMT 2000]

Options:

A) $1 \times 10^{- 4} m o l l^{- 1} s^{- 1}$

B) $3 \times 10^{- 4} m o l l^{- 1} s^{- 1}$

C) $4 \times 10^{- 4} m o l l^{- 1} s^{- 1}$

D) $6 \times 10^{- 4} m o l, l^{- 1} s^{- 1}$

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Answer:

Correct Answer: B

Solution:

$N_{2} + 3 H_{2}$ ⇌ $2 N H_{3}$

$\frac{- Δ [N_{2}]}{Δ t} = - \frac{1}{3} \frac{Δ [H_{2}]}{Δ t} = \frac{1}{2} \frac{Δ [N H_{3}]}{Δ t}$
$∴ \frac{Δ [H_{2}]}{Δ t} = \frac{3}{2} \times \frac{Δ [N H_{3}]}{Δ t} = \frac{3}{2} \times 2 \times 10^{- 4}$

$= 3 \times 10^{- 4} m o l l i t r e^{- 1} s e c^{- 1}$

Chemical Kinetics Question 240

Question: For the reaction $N_{2} + 3 H_{2} \to 2 N H_{3}$ if $\frac{Δ [N H_{3}]}{Δ t} = 2 \times 10^{- 4} m o l, l^{- 1} s^{- 1},$ the value of $\frac{- Δ [H_{2}]}{Δ t}$ would be [MP PMT 2000]

Options:

Answer:

Solution:

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Chemical Kinetics Question 240

Question: For the reaction N2+3H2→2NH3 if Δ[NH3]Δt=2×10−4mol,l−1s−1, the value of −Δ[H2]Δt would be [MP PMT 2000]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

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Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: For the reaction $N_{2} + 3 H_{2} \to 2 N H_{3}$ if $\frac{Δ [N H_{3}]}{Δ t} = 2 \times 10^{- 4} m o l, l^{- 1} s^{- 1},$ the value of $\frac{- Δ [H_{2}]}{Δ t}$ would be [MP PMT 2000]