SATHEE: Chemical Kinetics Question 206

Chemical Kinetics Question 206

Question: The rate of a first order reaction is $1.5 \times 10^{- 2} m o l L^{- 1} {min}^{- 1}$ at 0.5 M concentration of the reactant. The half life of the reaction is [CBSE PMT 2004]

Options:

A) 8.73 min

B) 7.53 min

C) 0.383 min

D) 23.1 min

Show Answer

Answer:

Correct Answer: D

Solution:

Rate $(\frac{d x}{d t}) = K . c$ ; $1.5 \times 10^{- 2} = K \times 0.5$ For first order $K = \frac{1.5 \times 10^{- 2}}{0.5} = 3 \times 10^{- 2} min u t e^{- 1}$

$t_{1 / 2} = \frac{.693}{K} = \frac{.693}{3 \times 10^{- 2}} = 23.1 min u t e$ .

Chemical Kinetics Question 206

Question: The rate of a first order reaction is $1.5 \times 10^{- 2} m o l L^{- 1} {min}^{- 1}$ at 0.5 M concentration of the reactant. The half life of the reaction is [CBSE PMT 2004]

Options:

Answer:

Solution:

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Sample Mock Test

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Chemical Kinetics Question 206

Question: The rate of a first order reaction is 1.5×10−2 molL−1 min−1 at 0.5 M concentration of the reactant. The half life of the reaction is [CBSE PMT 2004]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The rate of a first order reaction is $1.5 \times 10^{- 2} m o l L^{- 1} {min}^{- 1}$ at 0.5 M concentration of the reactant. The half life of the reaction is [CBSE PMT 2004]