Chemical Kinetics Question 170

Question: After how many seconds will the concentration of the reactants in a first order reaction be halved, if the decay constant is $ 1\text{.155}\times 1{0^{\text{-3}}}{{\sec }^{-1}} $ [CBSE PMT 2000]

Options:

A) 100 sec

B) 200 sec

C) 400 sec

D) 600 sec

Show Answer

Answer:

Correct Answer: D

Solution:

$ t=\frac{2.303}{k}\log \frac{a}{a-x} $

$ t=\frac{2.303}{1.155\times {10^{-3}}}\log \frac{100}{100-50}=600\sec $



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