Chemical Kinetics Question 155
Question: The conversion of $ A\to B $ follows second order kinetics. Doubling the concentration of $ A $ will increase the rate of formation of $ B $ by a factor [MP PET 1999; DCE 1999; KCET 2001; BCECE 2005]
Options:
A) $ 1/4 $
B) 2
C) $ 1/2 $
D) 4
Show Answer
Answer:
Correct Answer: D
Solution:
$ r=k{{(A)}^{2}} $ , when concentration is doubled
$ r=k{{(2A)}^{2}}=k,4{{(A)}^{2}} $ the rate becomes 4 times.
