Chemical Kinetics Question 118
Question: Decay constant of a reaction is $ 1.1\times {10^{-9}}/\sec $ , then the half life of the reaction is
Options:
A) $ 1.2\times 10^{8} $
B) $ 6.3\times 10^{8} $
C) $ 3.3\times 10^{8} $
D) $ 2.1\times 10^{8} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ {t_{1/2}}=\frac{0.693}{k},\frac{0.693}{1.1\times {10^{-9}}}=6.3\times 10^{8} $ sec.
