SATHEE: Chemical Kinetics Question 118

Chemical Kinetics Question 118

Question: Decay constant of a reaction is $1.1 \times 10^{- 9} / \sec$ , then the half life of the reaction is

Options:

A) $1.2 \times 10^{8}$

B) $6.3 \times 10^{8}$

C) $3.3 \times 10^{8}$

D) $2.1 \times 10^{8}$

Show Answer

Answer:

Correct Answer: B

Solution:

$t_{1 / 2} = \frac{0.693}{k}, \frac{0.693}{1.1 \times 10^{- 9}} = 6.3 \times 10^{8}$ sec.

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