Chemical Bonding And Molecular Structure Question 477
Question: Correctly match is:
Options:
A) $ {d_{x^{2}-y^{2}}} $ atomic orbital - One nodal plane
B) $ p_{y} $ atomic orbital - Two nodal planes
C) $ {\sigma_{p_{x}}} $ molecular orbital - $ \Psi $ (gerade)
D) $ \pi p_{y}^{*} $ molecularorbital - $ \Psi $ (ungerade)
Show Answer
Answer:
Correct Answer: C
Solution:
- $ \sigma $ bonding molecular orbital is gerade due to having center of symmetry.
