Chemical Bonding And Molecular Structure Question 471

Question: The hybridization of atomic orbital’s of nitrogen in $ NO_2^{+},NO_2^{-} $ and $ NH_4^{+} $ are

Options:

A) $ sp^{2},sp^{3} $ and $ sp^{2} $ respectively

B) $ sp,sp^{2} $ and $ sp^{3} $ respectively

C) $ sp^{2},sp $ and $ sp^{3} $ respectively

D) $ sp^{2},sp^{3} $ and sp respectively

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ NO_2^{+}=\frac{1}{2}[5+0+0-1]=2sp; $

$ NO_2^{-}=\frac{1}{2}[5+0+1-0]=3sp; $

$ NH_4^{+}=\frac{1}{2}[5+4+0-1]=4sp^{3} $



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