SATHEE: Chemical Bonding And Molecular Structure Question 470

Chemical Bonding And Molecular Structure Question 470

Question: Arrange the following in decreasing order of their bond length, $O_{2}, O_{2}^{+}, O_{2}^{-}$ and $O_{2}^{2 -}$

Options:

A) $O_{2}^{2 -} < O_{2}^{-} < O_{2} + O_{2}^{+}$

B) $O_{2} < O_{2}^{2 -} < O_{2}^{-} < O_{2}^{+}$

C) $O_{2}^{+} < O_{2}^{-} < O_{2}^{2 -} < O_{2}$

D) $O_{2}^{+} < O_{2} < O_{2}^{-} < O_{2}^{2 -}$

Show Answer

Answer:

Correct Answer: D

Solution:

Bond order for $O_{2} = 2; O_{2}^{+} = 2.5$ $O_{2}^{-} = 1.5, O_{2}^{2 -} = 1$ correct order is $O_{2}^{+} < O_{2} < O_{2}^{-} < O_{2}^{2 -}$

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Chemical Bonding And Molecular Structure Question 470

Question: Arrange the following in decreasing order of their bond length, O2,O2+,O2− and O22−

Options:

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Question: Arrange the following in decreasing order of their bond length, $O_{2}, O_{2}^{+}, O_{2}^{-}$ and $O_{2}^{2 -}$