Chemical Bonding And Molecular Structure Question 470

Question: Arrange the following in decreasing order of their bond length, $ O_2,O_2^{+},O_2^{-} $ and $ O_2^{2-} $

Options:

A) $ O_2^{2-}<O_2^{-}<O_2+O_2^{+} $

B) $ O_2<O_2^{2-}<O_2^{-}<O_2^{+} $

C) $ O_2^{+}<O_2^{-}<O_2^{2-}<O_2 $

D) $ O_2^{+}<O_2<O_2^{-}<O_2^{2-} $

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Answer:

Correct Answer: D

Solution:

  • Bond order for $ O_2=2;O_2^{+}=2.5 $ $ O_2^{-}=1.5,O_2^{2-}=1 $ correct order is $ O_2^{+}<O_2<O_2^{-}<O_2^{2-} $


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