Chemical Bonding And Molecular Structure Question 449

Question: $ SF_2,SF_4 $ and $ SF_6 $ have the hybridization at sulphur atom respectively as:

Options:

A) $ sp^{2},sp^{3},sp^{2}d^{2} $

B) $ sp^{3},sp^{3},sp^{3}d^{2} $

C) $ sp^{3},sp^{3}d,sp^{3}d^{2} $

D) $ sp^{3},spd^{2},d^{2}sp^{3} $

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Answer:

Correct Answer: C

Solution:

  • Hybridisation:
  1. $ :{{\overset{\centerdot ,\centerdot }{\mathop{SF}},}_2}\Rightarrow \frac{1}{2}(6+2)=4=sp^{3} $
  2. $ :\overset{{}}{\mathop{SF}},{ _4}\Rightarrow \frac{1}{2}(6+4)=5=sp^{3}d $
  3. $ SF_6\Rightarrow \frac{1}{2}(6+6)=6=sp^{3}d^{2} $


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