SATHEE: Chemical Bonding And Molecular Structure Question 448

Chemical Bonding And Molecular Structure Question 448

Question: The group of molecules having identical shape is:

Options:

A) $P C l_{5}, I F_{5}, X e O_{2} F_{2}$

B) $B F_{3}, P C l_{3}, X e O_{3}$

C) $S F_{4}, X e F_{4}, C C l_{4}$

D) $C l F_{3}, X e O F_{2}, X e F_{3}^{+}$

Show Answer

Answer:

Correct Answer: D

Solution:

$C l F_{3} \overset{}{\to} H y b r i d i s a t i o n$

$= 3 + \frac{1}{2} [7 - 3] = 5 (s p^{3} d)$

$X e O F_{2} \overset{}{\to} H y b r i d i s a t i o n$

$= 3 + \frac{1}{2} [8 - 4] = 5 (s p^{3} d)$

$X e F_{3}^{-} \overset{}{\to} H y b r i d i s a t i o n$

$= 3 + \frac{1}{2} [8 - 3 - 1] = 5 (s p^{3} d)$ All molecules have $s p^{3} d$ hybridization and 2 lone pairs. Hence all have identical (T-shape).

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Chemical Bonding And Molecular Structure Question 448

Question: The group of molecules having identical shape is:

Options:

Answer:

Solution:

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