Chemical Bonding And Molecular Structure Question 448
Question: The group of molecules having identical shape is:
Options:
A) $ PCl_5,IF_5,XeO_2F_2 $
B) $ BF_3,PCl_3,XeO_3 $
C) $ SF_4,XeF_4,CCl_4 $
D) $ ClF_3,XeOF_2,XeF_3^{+} $
Show Answer
Answer:
Correct Answer: D
Solution:
- $ ClF_3\xrightarrow{{}}Hybridisation $
$ =3+\frac{1}{2}[7-3]=5(sp^{3}d) $
$ XeOF_2\xrightarrow{{}}Hybridisation $
$ =3+\frac{1}{2}[8-4]=5(sp^{3}d) $
$ XeF_3^{-}\xrightarrow{{}}Hybridisation $
$ =3+\frac{1}{2}[8-3-1]=5(sp^{3}d) $ All molecules have $ sp^{3}d $ hybridization and 2 lone pairs. Hence all have identical (T-shape).
