SATHEE: Chemical Bonding And Molecular Structure Question 434

Chemical Bonding And Molecular Structure Question 434

Question: Dipole moment of $H_{2} O$ is 1.85 D. If the bond angle is $105^{\circ}$ and $O - H$ bond length is $0.94 \overset{o}{A},$ , what is the magnitude of charge on the oxygen atom in water molecule-

Options:

A) $2 \times 10^{- 10} e s u$

B) $4.28 \times 10^{- 10} e s u$

C) $3.22 \times 10^{- 10} e s u$

D) $1.602 \times 10^{- 19} C$

Show Answer

Answer:

Correct Answer: C

Solution:

$μ = 1.85, D = 1.85 \times 10^{- 18} e s u, c m = q \times d$

$c o s 52.5^{\circ} = \frac{d}{0.94 \overset{^{\circ}}{A},} \Rightarrow d = 0.609 \times 0.94 \overset{^{\circ}}{A},$

$= 0.572 \overset{^{\circ}}{A},$
$∴, μ = q \times d$

$q_{1} = \frac{μ}{d} = \frac{1.85 D}{0.572 \overset{^{\circ}}{A},}$

$= \frac{1.85 \times 10^{- 18} e s u, c m}{0.572 \times 10^{- 8} c m}$

$= 3.2 \times 10^{- 10} e s u$

Chemical Bonding And Molecular Structure Question 434

Question: Dipole moment of $H_{2} O$ is 1.85 D. If the bond angle is $105^{\circ}$ and $O - H$ bond length is $0.94 \overset{o}{A},$ , what is the magnitude of charge on the oxygen atom in water molecule-

Options:

Answer:

Solution:

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Chemical Bonding And Molecular Structure Question 434

Question: Dipole moment of H2O is 1.85 D. If the bond angle is 105∘ and O−H bond length is 0.94Ao, , what is the magnitude of charge on the oxygen atom in water molecule-

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Dipole moment of $H_{2} O$ is 1.85 D. If the bond angle is $105^{\circ}$ and $O - H$ bond length is $0.94 \overset{o}{A},$ , what is the magnitude of charge on the oxygen atom in water molecule-