SATHEE: Chemical Bonding And Molecular Structure Question 365

Chemical Bonding And Molecular Structure Question 365

Question: Which of the following is paramagnetic

Options:

A) $B_{2}$

B) $C_{2}$

C) $N_{2}$

D) $F_{2}$

Show Answer

Answer:

Correct Answer: A

Solution:

Paramagnetic property arise through unpaired electron. $B_{2}$ molecule have the unpaired electron so it show paramagnetism.

$B_{2} \to$ $\underset{(2 unpaired electron)}{σ 1 s^{2} σ^{*} 1 s^{2}, σ 2 s^{2} σ^{*} 2 s^{2}, π 2 p_{x}^{1} = π 2 p_{y}^{1}},$

$C_{2} \to$ $\underset{(No unpaired electron)}{σ 1 s^{2} σ^{*} 1 s^{2}, σ 2 s^{2} σ^{*} 2 s^{2}, π 2 p_{x}^{2} . π 2 p_{y}^{2}},$

$N_{2} \to$ $\underset{(No unpaired electron)}{σ 1 s^{2} σ^{*} 1 s^{2}, σ 2 s^{2} σ^{*} 2 s^{2}, σ 2 p_{x}^{2}, π 2 p_{y}^{2} π 2 p_{z}^{2}},$

$F_{2} \to$ $\underset{(No unpaired electron)}{σ s^{2}, σ^{*} 1 s^{2}, σ 2 s^{2}, σ^{*} 2 s^{2}, σ 2 p_{x}^{2}, π 2 p_{y}^{2}, π 2 p_{z}^{2},},$

$π^{*} 2 p_{y}^{2}, π^{*} 2 p_{z}^{2}$

So only $B_{2}$ exist unpaired electron and show the paramagnetism.

Chemical Bonding And Molecular Structure Question 365

Question: Which of the following is paramagnetic

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Chemical Bonding And Molecular Structure Question 365

Question: Which of the following is paramagnetic

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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