Chemical Bonding And Molecular Structure Question 358

Question: Bond order of $ O_2 $ is

[DPMT 2004]

Options:

A) 2

B) 1.5

C) 3

D) 3.5

Show Answer

Answer:

Correct Answer: A

Solution:

Electronic configuration of $ O_2 $ is $ O_2={{(\sigma 1s)}^{2}}{{({{\sigma }^{}}1s)}^{2}}{{(\sigma 2s)}^{2}}{{({{\sigma }^{}}2s)}^{2}}{{({{\sigma }^{*}}2s)}^{2}}{{(\sigma 2p_{z})}^{2}} $

$ (\pi 2p_x^{2}\equiv \pi 2p_y^{2})\ ({{\pi }^{}}2p_x^{1}\equiv {{\pi }^{}}2p_y^{1}) $
Hence bond order $ =\frac{1}{2}[ N_{b}-N_{a} ] $

$ =\frac{1}{2}[10-6]=2 $ .



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