SATHEE: Chemical Bonding And Molecular Structure Question 244

Chemical Bonding And Molecular Structure Question 244

Question: The molecule of $C O_{2}$ has 180° bond angle. It can be explanid on the basis of [AFMC 2004]

Options:

A) $s p^{3}$ hybridisation

B) $s p^{2}$ hybridisation

C) $s p$ hybridisation

D) $d^{2} s p^{3}$ hybridization

Show Answer

Answer:

Correct Answer: C

Solution:

$C_{ground state} = 2 s^{2}, 2 p_{x}^{1} p_{y}^{1}$ ; $C_{excited state} = 2 s^{1}, 2 p_{x}^{1} p_{y}^{1} p_{z}^{1}$

$O_{ground state} = 2 s^{2}, 2 p_{x}^{2} p_{y}^{1} p_{z}^{1}$ In the formation of $C O_{2}$ molecule, hybridization of orbitals of carbon occur only to a limited extent involving only one s and one p orbitals there is thus sp hybridisation of valence shell orbitals of the carbon atom resulting in the formation of two sp hybrid orbitals.

Chemical Bonding And Molecular Structure Question 244

Question: The molecule of $C O_{2}$ has 180° bond angle. It can be explanid on the basis of [AFMC 2004]

Options:

Answer:

Solution:

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Chemical Bonding And Molecular Structure Question 244

Question: The molecule of CO2 has 180° bond angle. It can be explanid on the basis of [AFMC 2004]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The molecule of $C O_{2}$ has 180° bond angle. It can be explanid on the basis of [AFMC 2004]