Chemical Bonding And Molecular Structure Question 240

Question: In an octahedral structure, the pair of d orbitals involved in $ d^{2}sp^{3} $ hybridization is [CBSE PMT 2004]

Options:

A) $ {d_{x^{2}}},d_{xz} $

B) $ d_{xy},d_{yz} $

C) $ {d_{x^{2}-y^{2}}},{d_{z^{2}}} $

D) $ d_{xz},{d_{x^{2}-y^{2}}} $

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Answer:

Correct Answer: C

Solution:

In the formation of $ d^{2}sp^{3} $ hybrid orbitals two $ (n-1)d $ orbitals of e.g., set [i.e., $ (n-1),dz^{2} $ and $ (n-1)dx^{2}-y^{2} $ orbitals] one ns and three np [ $ np_{x},np_{y} $ and $ np_{z} $ ] orbitals combine together and form six $ d^{2}sp^{3} $ hybrid orbitals.



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