Chemical Bonding And Molecular Structure Question 222

Question: As the s-character of hybridisation orbital increases, the bond angle

Options:

A) Increases

B) Decreases

C) Becomes zero

D) Does not change

Show Answer

Answer:

Correct Answer: A

Solution:

s-character increases with increase in bond angle. Hybridization s% Angle Sp 50 $ 180^{o} $

$ sp^{2} $ 33.3 $ 120^{o} $

$ sp^{3} $ 25 $ {{109.28}^{o}} $

$ sp^{3}d^{1} $ 20 $ 90^{o} $ and $ 120^{o} $



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