Atomic Structure Question 92

Question: Number of protons, neutrons and electrons in the element $ _{89}^{231}Y $ is [AFMC 1997]

Options:

A) 89, 231, 89

B) 89, 89, 242

C) 89, 142, 89

D) 89, 71, 89

Show Answer

Answer:

Correct Answer: C

Solution:

In $ Xe _{89} ^{231} $ number of protons and electrons is 89 and No. of neutrons = A - Z = 231 - 89 = 142.



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