Atomic Structure Question 92
Question: Number of protons, neutrons and electrons in the element $ _{89}^{231}Y $ is [AFMC 1997]
Options:
A) 89, 231, 89
B) 89, 89, 242
C) 89, 142, 89
D) 89, 71, 89
Show Answer
Answer:
Correct Answer: C
Solution:
In $ Xe _{89} ^{231} $ number of protons and electrons is 89 and No. of neutrons = A - Z = 231 - 89 = 142.