SATHEE: Atomic Structure Question 67

Atomic Structure Question 67

Question: The atomic weight of an element is double its atomic number. If there are four electrons in $2 p$ orbital, the element is

[AMU 1983]

Options:

A) $C$

B) $N$

C) $O$

D) $C a$

Show Answer

Answer:

Correct Answer: C

Solution:

$_{8} O = 1 s^{2} 2 s^{2} 2 p^{4}$

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Atomic Structure Question 67

Question: The atomic weight of an element is double its atomic number. If there are four electrons in 2p orbital, the element is

Options:

Answer:

Solution:

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Question: The atomic weight of an element is double its atomic number. If there are four electrons in $2 p$ orbital, the element is