Atomic Structure Question 463

Question: If electron falls from $ n=3 $ to $ n=2 $ , then emitted energy is

Options:

A) $ 10.2eV $

B) $ 12.09eV $

C) $ 1.9eV $

D) $ 0.65eV $

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Answer:

Correct Answer: C

Solution:

  • $ \Delta E=E_3-E_2=13.6,[ \frac{1}{{{(2)}^{2}}}-\frac{1}{{{(3)}^{2}}} ]=1.9,eV $


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