Atomic Structure Question 46

Question: Time taken for an electron to complete one revolution in the Bohr orbit of hydrogen atom is [Kerala PMT 2004]

Options:

A) $ \frac{4{{\pi }^{2}}mr^{2}}{nh} $

B) $ \frac{nh}{4{{\pi }^{2}}mr} $

C) $ \frac{nh}{4{{\pi }^{2}}mr^{2}} $

D) $ \frac{h}{2\pi mr} $

Show Answer

Answer:

Correct Answer: A

Solution:

It will take $ \frac{4{{\pi }^{2}}mr^{2}}{n,h} $



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