Atomic Structure Question 429

Question: An electron travels with a velocity of xms1. For a proton to have the same de-Broglie wavelength, the velocity will be approximately:

Options:

A) 1840x

B) x1840

C) 1840x

D) x

Show Answer

Answer:

Correct Answer: B

Solution:

  • λ=hmex=hmpV=h1840meV

[mp=1840me]
Hence, V=x1840



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