Atomic Structure Question 395

Question: In a hydrogen atom, if energy of an electron in ground state is 13.6. ev, then that in the 2nd excited state is

Options:

A) $ 1.51eV $

B) $ 3.4,eV $

C) $ 6.04,eV $

D) $ 13.6eV $

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Answer:

Correct Answer: A

Solution:

  • 2nd excited state will be the 3rd energy level. $ E_{n}=\frac{13.6}{n^{2}}eV,or,E=\frac{13.6}{9}eV=1.51,eV. $


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