SATHEE: Atomic Structure Question 393

Atomic Structure Question 393

Question: When electronic transition occurs from higher energy state to lower energy state with energy difference equal to $Δ E$ electron volts, the wavelength of the line emitted is approximately equal to

Options:

A) $\frac{12395}{Δ E} \times 10^{- 10} m$

B) $\frac{12395}{Δ E} \times 10^{10} m$

C) $\frac{12395}{Δ E} \times 10^{- 10} c m$

D) $\frac{12395}{Δ E} \times 10^{10} c m$

Show Answer

Answer:

Correct Answer: A

Solution:

$λ = \frac{h c}{Δ E}$

$= \frac{6.62 \times 10^{- 34} J s \times 3 \times 10^{8} m s^{- 1}}{E \times 1.602 \times 10^{- 19} J}$

$= \frac{12395}{E} \times 10^{- 10} m$

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Atomic Structure Question 393

Question: When electronic transition occurs from higher energy state to lower energy state with energy difference equal to ΔE electron volts, the wavelength of the line emitted is approximately equal to

Options:

Answer:

Solution:

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Question: When electronic transition occurs from higher energy state to lower energy state with energy difference equal to $Δ E$ electron volts, the wavelength of the line emitted is approximately equal to