Atomic Structure Question 386

Question: An electron, e1 is moving in the fifth stationary state, and another electro e2 is moving in the fourth stationary state. The radius of orbit of electron e1 is five times the radius of orbit of electron, e2 calculate the ratio of velocity of electron e1(v1) to the velocity of electron e2(v2)

Options:

A) 5 : 1

B) 4 : 1

C) 1 : 5

D) 1 : 4

Show Answer

Answer:

Correct Answer: D

Solution:

  • From the expression of Bohr’s theory, we know that mev1r1=n1h2π

&,mev2r2=n2h2π

mev1r1mev2r2=n1n2h2π×2πh Given, r1=5r2,,n1=5,n2=4

me×v1×5r2me×v2×r2=54
v1v2=54×5=14=1:4



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