Atomic Structure Question 384

Question: Excited hydrogen atom emits light in the ultraviolet region at $ 2.47\times 10^{15}Hz $ . With this frequency, the energy of a single photon is: $ (h=6.63\times {10^{-34}}Js) $

Options:

A) $ 8.041\times {10^{-40}}J $

B) $ 2.680\times {10^{-19}}J $

C) $ 1.640\times {10^{-18}}J $

D) $ 6.111\times {10^{-17}}J $

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Answer:

Correct Answer: C

Solution:

  • $ E=hv $

$ =6.63\times {10^{-34}}\times 2.47\times 10^{15} $

$ =1.640\times {10^{-18}}J $



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