SATHEE: Atomic Structure Question 381

Atomic Structure Question 381

Options:

A) $λ = \frac{λ_{1} + λ_{2}}{λ_{1} λ_{2}}$

B) $λ = \frac{λ_{1} λ_{2}}{λ_{1} + λ_{2}}$

C) $λ = \frac{{λ_{1}}^{2} {λ_{2}}^{2}}{λ_{1} + λ_{2}}$

D) $λ = \frac{λ_{1} λ_{2}}{{(λ_{1} + λ_{2})}^{2}}$

Show Answer

Answer:

Correct Answer: B

Solution:

$E = E_{1} + E_{2};$

$\frac{h c}{λ} = \frac{h c}{λ_{1}} + \frac{h c}{λ_{2}}$
$\Rightarrow \frac{h c}{λ} = h c (\frac{λ_{2} + λ_{1}}{λ_{1} λ_{2}}); λ = \frac{λ_{1} λ_{2}}{λ_{1} + λ_{2}}$

Atomic Structure Question 381

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Atomic Structure Question 381

Question: A dye absorbs a photon of wavelength λ and re-emits the same energy into two photons of wavelength λ1 and λ2 respectively. The wavelength λ is related with λ1 and λ2 as:

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: A dye absorbs a photon of wavelength $λ$ and re-emits the same energy into two photons of wavelength $λ_{1}$ and $λ_{2}$ respectively. The wavelength $λ$ is related with $λ_{1}$ and $λ_{2}$ as: