SATHEE: Atomic Structure Question 379

Atomic Structure Question 379

Question: In an atom, an electron is moving with a speed of 600 m/s with an accuracy of 0.005%. Certainity with which the position of the electron can be located is ( $h = 6.6 \times 10^{- 34} k g, m^{2} s^{- 1}$ , mass of electron, $e_{m} = 9.1 \times 10^{- 31} k g$ )

Options:

A) $5.10 \times 10^{- 3} m$

B) $1.92 \times 10^{- 3} m$

C) $3.84 \times 10^{- 3} m$

D) $1.52 \times 10^{- 4} m$

Show Answer

Answer:

Correct Answer: B

Solution:

According to Heisenberg uncertainty principle. $Δ x . m Δ v = \frac{h}{4 π}$

$Δ x = \frac{h}{4 π m Δ v}$ Here $Δ v = \frac{600 \times 0.005}{100} = 0.03$ So, $Δ x = \frac{6.6 \times 10^{- 34}}{4 \times 3.14 \times 9.1 \times 10^{- 31} \times 0.03}$

$= 1.92 \times 10^{- 3}$

Atomic Structure Question 379

Question: In an atom, an electron is moving with a speed of 600 m/s with an accuracy of 0.005%. Certainity with which the position of the electron can be located is ( $h = 6.6 \times 10^{- 34} k g, m^{2} s^{- 1}$ , mass of electron, $e_{m} = 9.1 \times 10^{- 31} k g$ )

Options:

Answer:

Solution:

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NCERT Books & Solutions

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NCERT Exercise Video Solution

Atomic Structure Question 379

Question: In an atom, an electron is moving with a speed of 600 m/s with an accuracy of 0.005%. Certainity with which the position of the electron can be located is ( h=6.6×10−34kg,m2s−1 , mass of electron, em=9.1×10−31kg )

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: In an atom, an electron is moving with a speed of 600 m/s with an accuracy of 0.005%. Certainity with which the position of the electron can be located is ( $h = 6.6 \times 10^{- 34} k g, m^{2} s^{- 1}$ , mass of electron, $e_{m} = 9.1 \times 10^{- 31} k g$ )