Atomic Structure Question 349

Question: The number of unpaired electrons in $ F{e^{3+}}(Z=26) $ are [KCET 2000]

Options:

A) 5

B) 6

C) 3

D) 4

Show Answer

Answer:

Correct Answer: A

Solution:

$ F{e^{3+}} $

$ (z=26) $

$ F{e^{3+}}=[Ar],3d^{5}4s^{0} $ Total no. of unpaired electron=5



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