Atomic Structure Question 349
Question: The number of unpaired electrons in $ F{e^{3+}}(Z=26) $ are [KCET 2000]
Options:
A) 5
B) 6
C) 3
D) 4
Show Answer
Answer:
Correct Answer: A
Solution:
$ F{e^{3+}} $
$ (z=26) $
$ F{e^{3+}}=[Ar],3d^{5}4s^{0} $ Total no. of unpaired electron=5