Atomic Structure Question 336

Question: $ 3d^{10}4s^{0} $ electronic configuration exhibits by

Options:

A) $ Z{n^{++}} $

B) $ C{u^{++}} $

C) $ C{d^{++}} $

D) $ H{g^{++}} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ Zn_{30}=[Ar],3d^{10}4s^{2} $

$ Z{n^{++}}=,[Ar],3d^{10},4s^{0} $



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