Atomic Structure Question 33
Question: If change in energy $ (\Delta E)=3\times {10^{-8}}J,h=6.64\times {10^{-34}}J\text{-}s $ and $ c=3\times 10^{8},m/s, $ then wavelength of the light is [CBSE PMT 2000]
Options:
A) $ 6.36\times 10^{3} \AA $
B) $ 6.36\times 10^{5} \AA $
C) $ 6.64\times {10^{-8}} \AA $
D) $ 6.36\times 10^{18} \AA $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \Delta E=\frac{hc}{\lambda } $ or $ \lambda =\frac{hc}{\Delta E} $
$ =\frac{6.64\times {10^{-34}}\times 3\times 10^{8}}{3\times {10^{-8}}}=6.64\times {10^{-8}}{\AA} $
